[SamLovesBrian14]

I need help on these, I never understand things like this.

how do I find the answer to linear equations such as..

x+y=6
y=x+1
y=x-2
x+2=y

you help me and ill try to help you! :)

[ballengerb1]

I don't think this is possible "y=x+1, y=x-2
"

[Unknown008]

Do... you have to graph these? :confused:

[rosanna-hope]

if its y = x then it goes through the center of the graph, when its y=x+1 you move the line or point up one place on the x axis

and the same with the y=x-2 except instead of adding 1 you mius 2 from the center

[mathwiz3502]

Like everyone is saying, please be more specific, but here are the characteristics of the equations you posted in relation to x=y which is a 45 degree diagonal line going through the origin (0,0)
1.x+y=6, 6 units above
2.y=x+1, 1 unit above
3.y=x-2, 2 units below
4.x+2=y, 2 units above
If this does not help, I recommend asking about the 6 parent functions to either us or your teacher.

[mathwiz3502]

x=y also goes from the bottom left corner to the top right corner

[mathwiz3502]

OH, my bad, x+y=6 is 6 units below

[mathwiz3502]

Sorry, x+y=6 is flipped over the y axis and up 6 units

[QLP]

Ok this is how I would think about it.
If you take x+y=6 first:
When x=0,y=6 so you can put a cross on the graph at (0,6)
When y=0, x=6, so you can put another cross on the graph at (6,0)
Now you have two points on the graph so you can draw a straight line through them.

Repeat for all the other equations by making first x and then y equal to 0 to see what the other co-ordinate is and then you will have all the points you need to draw all the lines.

If any part of that isn't clear I will try to clarify further.