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    sarah1004's Avatar
    sarah1004 Posts: 107, Reputation: 1
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    #1

    Nov 2, 2009, 09:21 AM
    write a balanced reaction between Ba(OH)2 and H2SO4.
    write a balanced reaction between Ba(OH)2 and H2SO4.
    ----> Ba(OH)2(aq) + H2SO4(aq) => BaSO4(s) + 2H2O(l)

    explain the observed changes in conductivity.
    ----> H2SO4-strong conductivity. Ba(OH)2-weak conductivity.

    Please check these answers are correct or not , if not please explain for me

    Thanks
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #2

    Nov 2, 2009, 10:05 AM

    Well, at first you had Ba(SO4)2 and H2SO4 which are both electrolytes. Then, you have BaSO4 which is a solid, insoluble in water. A solid does not conduct electricity, nor does pure water. So, conductivity decreases.
    sarah1004's Avatar
    sarah1004 Posts: 107, Reputation: 1
    Junior Member
    		  
    #3

    Nov 2, 2009, 10:11 AM
    write a balanced reaction between Ba(OH)2 and H2SO4.
    ----> Ba(OH)2(aq) + H2SO4(aq) => BaSO4(s) + 2H2O(l)

    So, this equation is correct?


    Thanks for your explain
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #4

    Nov 2, 2009, 10:16 AM

    Yup, you can self check it. Count the number of Ba, H, S, O on the right and then on the left. You'll see they are equal in number.
    sarah1004's Avatar
    sarah1004 Posts: 107, Reputation: 1
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    #5

    Nov 2, 2009, 10:19 AM
    Yes its perfectly balanced!

    Thanks
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #6

    Nov 2, 2009, 10:23 AM

    You're welcome :)
    pramod awasthi's Avatar
    pramod awasthi Posts: 29, Reputation: -1
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    #7

    Nov 9, 2009, 05:52 AM

    reaction is
    Ba(OH)2 + H2SO4 ====> BaSO4 + 2H2O
    it is a balane equation and coductivity is depand upon capacity to dissociate in to ions. An BaSO4 have less capabilty to produce ions than H2SO4 and Ba(OH)4
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