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    13McNugget's Avatar
    13McNugget Posts: 1, Reputation: 1
    New Member
    		  
    #1

    Sep 21, 2009, 02:03 PM
    having hard time
    solve for y

    y-6x=-1
    3y-5x=9
    Perito's Avatar
    Perito Posts: 3,139, Reputation: 150
    Ultra Member
    		  
    #2

    Sep 21, 2009, 02:05 PM

    1. Multiply each item in the first equation by -3.
    2. Add the two equations, item by item.
    3. Y will be eliminated. Solve for X

    alternately
    1. Multiply each item in the first equation by 3
    2. Subtract the two equations, item by item.
    3. Y will be eliminated. Solve for X.
    shauna1989's Avatar
    shauna1989 Posts: 1, Reputation: 1
    New Member
    		  
    #3

    Sep 23, 2009, 08:01 AM

    if I had 2 green balls and 5 red balls what's the probability of getting a green then red
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
    Uber Member
    		  
    #4

    Sep 23, 2009, 09:28 AM

    Hi shauna1989! Welcome to AMHD! :)

    You should have started another thread for your question...

    Anyway, concerning your problem:

    You have 7 balls in all.
    The probability of having a green ball is 2/7.
    Now that you removed a ball, there are 6 left.
    The probability of having a red ball now is 5/6.

    Since it is one probability immediately followed by the other one without replacing the first ball, you multiply both probabilities: 2/7 * 5/6 = 10/42 = 5/21
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