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    Wondergirl's Avatar
    Wondergirl Posts: 39,354, Reputation: 5431
    Jobs & Parenting Expert
     
    #61

    Aug 8, 2009, 05:16 PM
    Quote Originally Posted by Romefalls19 View Post
    Yep we did! Now we can relax and spend the night together!
    But I have other plans. Could you spend it with Mrs. Romefalls instead?
    Romefalls19's Avatar
    Romefalls19 Posts: 4,739, Reputation: 1130
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    #62

    Aug 8, 2009, 05:17 PM

    Well played
    Wondergirl's Avatar
    Wondergirl Posts: 39,354, Reputation: 5431
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    #63

    Aug 8, 2009, 05:22 PM
    Quote Originally Posted by Romefalls19 View Post
    well played
    Have a great evening, and wave to my mom in Hamlin. She's the one in the red dress and standing on the roof of her car waving back.
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    Romefalls19 Posts: 4,739, Reputation: 1130
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    #64

    Aug 8, 2009, 05:23 PM

    Ha ha will do.. Enjoy your night!
    morgaine300's Avatar
    morgaine300 Posts: 6,561, Reputation: 276
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    #65

    Aug 8, 2009, 09:21 PM

    Wondergirl - must've given you a greenie recently & don't remember...

    But I just wanted to say I'm impressed you stuck with this. I can't guarantee staying on here long enough to have a back to forth with someone and therefore work through that much stuff. (In person or on a chat, sure, but not on here.)
    Wondergirl's Avatar
    Wondergirl Posts: 39,354, Reputation: 5431
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    #66

    Aug 8, 2009, 09:29 PM
    Quote Originally Posted by morgaine300 View Post
    Wondergirl - must've given you a greenie recently & don't remember...

    But I just wanted to say I'm impressed you stuck with this. I can't guarantee staying on here long enough to have a back to forth with someone and therefore work thru that much stuff. (In person or on a chat, sure, but not on here.)
    Thanks, morgaine. You gave me a greenie on 07/15/09.

    Romefalls is an AMHD buddy and is from the part of the world that I grew up in, so I took pity on him. And this question has gotten 212 views so far lol.
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #67

    Aug 9, 2009, 05:36 AM

    Should I? Or shouldn't I? Ok, I dare.

    The perimeter of a rectangle is given by shorter length + longer length + shorter length + longer length.

    If you look well, you can also write it this way:

    Perimeter of rectangle = 2 x (shorter length + longer length)

    That's a sort of shortcut.

    I'll take the 60 perimeter carpet.

    Perimeter = 2 (x + x + 10) = 60

    That simplifies to x + x + 10 = 30 (you divide both sides by two to get rid of the '2')

    That makes 2x + 10 = 30

    Then, solving for x gives you 10 for the shorter side, and (x + 10) gives 20 for the longer length.

    :)
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    Wondergirl Posts: 39,354, Reputation: 5431
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    #68

    Aug 9, 2009, 09:27 AM
    Quote Originally Posted by Unknown008 View Post
    Should I? or shouldn't I? Ok, I dare.
    Yeah, we know. You came too late to the math party.
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    Unknown008 Posts: 8,076, Reputation: 723
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    #69

    Aug 10, 2009, 08:37 AM

    Sigh, I know. The thing is that, when Rome posted this, it was 1.42 am for me, I was sleeping! Well, that's the big disadvantage of these time differences, lol! :p
    Wondergirl's Avatar
    Wondergirl Posts: 39,354, Reputation: 5431
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    #70

    Aug 10, 2009, 09:23 AM
    Quote Originally Posted by Unknown008 View Post
    Sigh, I know. The thing is that, when Rome posted this, it was 1.42 am for me, I was sleeping! Well, that's the big disadvantage of these time differences, lol! :p
    I was just reading about your country. It sounds beautiful, a wonderful place to live!
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #71

    Aug 10, 2009, 09:30 AM

    Okay, your post is the second of its kind of the week. The first was from firmbeliever. Thanks anyway :)

    Except that the education system lags behind. I was given a math paper for 11 and 12 yo students of Australia, and that seemed so difficult for me and I thought that the aussies were far 'advanced' in that subject! :eek: And morgaine, and galactus then told me that there were more countries 'far advanced' sigh... :(
    morgaine300's Avatar
    morgaine300 Posts: 6,561, Reputation: 276
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    #72

    Aug 10, 2009, 01:51 PM
    Quote Originally Posted by Unknown008 View Post
    Except that the education system lags behind. I was given a math paper for 11 and 12 yo students of Australia, and that seemed so difficult for me and I thought that the aussies were far 'advanced' in that subject! :eek: And morgaine, and galactus then told me that there were more countries 'far advanced' sigh... :(
    OK, wait. 11 and 12 yo? You said 11th & 12th grade on the other post, didn't you?
    lol142's Avatar
    lol142 Posts: 1, Reputation: 1
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    #73

    Aug 11, 2009, 12:01 AM

    Don't know if you still need this or not... but here's the answers to all 6 with algebraic explanation for reference:

    1) Leah makes $24 per hour for a 40-hour week and time and a half for every hour over 40 hours. If she made $1140 last week, how many overtime hours did she work?

    You know that the amount that Leah makes per week is a constant in this problem. Since she is working overtime, she's already finished her 40 hours. So, we know that she already made 24 x 40 dollars per week.

    We also know that she makes time and a half or 150% for every hour she works overtime. So her wages for working overtime are 1.5 x 24 because 24 is her normal hourly wage and multiplying that by the rate (1.5) gives her overtime wage rate.

    But, since she gets that rate every hour she works, and we want to find how many hours of overtime she works, we define the variable "h" as hours of overtime Leah works and multiply it by the rate of 1.5 x 24 to get 1.5 x 24h

    The last piece of given information was that she receives 1140 dollars during that week. So, whatever the formula used for computing her wages must be set equal to 1140.

    So now, we have enough information to create an equation for this problem:

    24 x 40 + 24 x 1.5h = 1140

    Simplify to get:

    960 +36h = 1140

    Add -960 to both sides to get:

    36h = 180

    Multiply both sides by 1/36 to reveal that:

    h = 5

    So she worked 45 hours last week and 5 of them were overtime :)

    2) Four less than nine times a number is one hundred twenty-two. Find the original number.

    Okay, let's call the original number n. Now translate the "key" words in the problem. Less than means subtract. Times means multiply. Is means equals.

    To put that in an equation, you get:

    9n - 4 = 122

    Adding 4 to both sides gets:

    9n = 126

    Multiplying by 1/9 reveals:

    n = 14

    So the original number is 14. To check, multiply it by 9 to get 126, then subtract 4 to get 122 :)

    3) The cost of renting a subcompact car from Super Rental is $20 a day plus 25 cents per mile. How far can Allison drive in one day if she has only $75?

    So the cost no matter what is going to be 20 dollars since she only rented the car for 1 day. Even if she drives 0 miles, she'll still have to pay 20 dollars.

    In addition, for every mile she drives, she must pay 25 cents. So the rate is $.25 to keep the units consistent. . 25m will give the cost of driving m miles not including the 20 dollar fee for renting the car.

    We also know that she cannot exceed 75 dollars. The largest mileage will be the amount that allows the equation to equal 75. You don't need an inequality here, though if you really wanted to you could... but there's no point in cluttering up the problem.

    So the equation is:

    20 + .25m = 75

    Add -20 to both sides to get:

    .25m = 55

    Multiply both sides by 4 to find that:

    m = 220

    So she can drive 220 miles (or less) :)

    4) The length of a rectangular field is 50 meters more than twice its width. If the perimeter is 700 meters, find the dimensions of the field.

    This one's a little trickier because it requires a systems of linear equations. The first equation relates the side lengths to each other and the second is the formula for perimeter.

    Let L = the length of the field.

    Let W = the width of the field.

    We know that the length is 50 meters plus 2 times the width. So the first equation is:

    50 + 2w = L

    The second equation is the formula for perimeter. In case you've forgotten:

    2L + 2W = Perimeter

    Since we know that the perimeter is 700, by substitution:

    2L + 2W = 700

    Great! We now have 2 equations and 2 unknowns. We can solve them simultaneously now. Here are the 2 equations set up on top of each other:

    2w + 50 = L
    2L + 2W = 700

    (The systems of equations will be displayed without an extra line of white space between them)

    You can solve this by elimination or substitution. Personally, I like substitution better, so I'll use that.

    We know that L = 2w + 50, so we'll replace L in the second equation with "(2w + 50)" as shown:

    2 ( 2w + 50 ) + 2w = 700

    Distribute the 2:

    4w + 100 + 2w = 700

    Combine like terms:

    6w + 100 = 700

    Add -100 to both sides:

    6w = 600

    Multiply by 1/6:

    w = 100

    Now you can substitute for the length:

    2W + 50 = L

    2(100) + 50 = L

    200 + 50 = L

    250 = L

    So the width is 100 meters and the length is 250 meters :)

    5) A wire measures 84 centimeters in length. It is cut into two pieces. The shorter piece is 6 centimeters shorter than the long piece. Find the length of each piece.

    Another systems problem. This one could also be done with guess and check or logically, but here's the algebraic solution:

    Call the length of one wire n and the other length m.

    n + m therefore = 84

    and n = m + 6, since one of the wires is 6 cm longer than the other. It doesn't matter whether the 6 is subtracted or added, or even which side it's on. Choose your preferences.

    So the systems is:

    n + m = 84
    n = m + 6

    I'm going to use substitution again:

    Substituting "(m + 6)" for n in the first equation gives the single equation:

    ( m + 6 ) + m = 84

    This is easily solved:

    2m + 6 = 84

    2m = 78

    m = 39

    Since n is 6 cm longer, n = 45.

    So the shorter piece is 39 cm and the longer wire is 45 centimeters :)

    6) Create a real-life problem that involves linear equations and provide a solution to the problem.

    This one is about as easy as you can get. Do a taxicab problem and model it after the car rental problem. Just substitute the 20 dollar day fee to the base fee for taxi services and the .25 cent rate to whatever you want, then put the amount of money you have on the right side and see how many miles you could ride with that amount of money. Solve it the same way :)

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