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    Kan418's Avatar
    Kan418 Posts: 4, Reputation: 1
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    #1

    Jul 19, 2009, 01:27 PM
    instantaneous rate of change
    total amount of money in circulation for years 1950-2004 -
    M(t) = 3.044t^3 + 14,274.5t-139,433 where t represents number of years since 1950 and M9t) is millions of dollars
    1- How much money was in circulation in the year 1985
    2- What was the instantaneous rate of change of the amount of money in circulation in the year 2002?
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #2

    Jul 20, 2009, 07:10 AM
    1. Find the number of years from 1950 to 1985. With that number of years, plug in that value in your equation and you'll get the amount of money in 1985.

    2. Rate of change is given by the derivative of your equation. You should also know the amount of years there are from 1950 to 2002. Plug the amount of years in your derivative and you'll have the rate of change of the money.

    I'd like to ask you if that is really the equation given. Clearly, the equation says that in 1950, there were 'a debt' in the circulating money... :confused:
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
    Uber Member
    		  
    #3

    Jul 20, 2009, 07:11 AM
    1. Find the number of years from 1950 to 1985. With that number of years, plug in that value in your equation and you'll get the amount of money in 1985.

    2. Rate of change is given by the derivative of your equation. You should also know the amount of years there are from 1950 to 2002. Plug the amount of years in your derivative and you'll have the rate of change of the money.

    I'd like to ask you if that is really the equation given. Clearly, the equation says that in 1950, there were 'a debt' in the circulating money... :confused:

    EDIT: oops, double posted... :o
    Kan418's Avatar
    Kan418 Posts: 4, Reputation: 1
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    #4

    Jul 20, 2009, 07:48 AM
    Thank you
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