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    thinay's Avatar
    thinay Posts: 40, Reputation: 2
    Junior Member

    Jul 3, 2009, 08:11 AM
    ellipse and hyperbola
    The equation of a hyperbola is like this:
    x^2/a^2 - y^2/b^2 = 1

    my problem is this.. I don't know what am I going to do with this equation > 4x^2 - y^2 = 4y
    to become same as the equation above.. I am confused because of the 4y..
    After that, I will find the center, vertices, foci and asymptote of that equation.

    Another problem. (in ellipse)
    Same as the above problem about the equation.
    4x^2 + y^2 = 8x
    Because of 8x there, I don't know how am I going to do that same like this:
    (x-h)^2/a^2 + (y-k)^2/b^2=1

    After that, I will also going to find its center, foci and semi axes.

    Hope you can help me. Thanks! :)
    galactus's Avatar
    galactus Posts: 2,271, Reputation: 282
    Ultra Member

    Jul 3, 2009, 09:05 AM
    Complete the square.

    For the ellipse.

    Complete the square:

    Factor what's in the parentheses and divide by 4:

    There is the ellipse equation. See the center and lengths of axes?

    Try the same method with your hyperbola

    Here is a graph of your ellipse:
    Attached Images
    thinay's Avatar
    thinay Posts: 40, Reputation: 2
    Junior Member

    Jul 4, 2009, 03:14 AM

    Thanks for your help galactus! :)

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