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HannahFisher · Jun 25, 2009, 03:39 PM

x2-11+10

x2-64

Please leave a simple explination, on how to do them:)

jenniepepsi · Jun 25, 2009, 03:42 PM

First... we can't do your homework for you...

Second... I REALLY and Truly hope that your screen name is not your REAL first and LAST name...

Try to work the problems out yourself, and we can check your answers for you :)

galactus · Jun 25, 2009, 04:34 PM

$x^{2}-11+10$

Here is an example worked out, so you can see to do yours:

Factor: $x^{2}-5x+6$

What two numbers when added equals -5 and when multiplied equals 6?

How about -3 and -2? (-3)(-2)=6 and -3+(-2)=-5

$x^{2}-3x-2x+6$

Group:

$(x^{2}-3x)-(2x-6)$

Factor out something common from each parentheses:

$x(x-3)-2(x-3)$

See? What's in the parentheses is the same. That is crucial for it to work.

$(x-2)(x-3)$

There... all done. Now you try with yours.

$x^{2}-64$

This is just the difference of two squares factorization. $x^{2}-y^{2}=(x+y)(x-y)$

ArcSine · Jun 26, 2009, 07:01 AM

Yep, almost certainly Hannah intended $\ x^2 -11x + 10$

... but just on the outside chance it was written up exactly as intended, she's back to a simple diff of two squares.