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Algebra 2
Please show me how to answer this. I don't have a clue.
Mr. Lindle invested his $210,000 retirement funds in two bonds, one yielding 8% and one yielding 10%. If his total annual income from both investments is $18,300 how much did he invest at each rate? :confused: |
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Let x=the amount invested at 8%
Then, 210000-x is the remaining amount invested at 10%. So, we have .08x+.10(210000-x)=18300 Solve for x. |
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