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    natalie1xxx's Avatar
    natalie1xxx Posts: 120, Reputation: 3
    Junior Member
    		  
    #1

    Jun 16, 2009, 02:00 PM
    Address bus calculation ?
    How do I answer this question :eek:... "if a computer had a 12-bit address bus, how many different memory locations could it address directly?"... thanks :D:D
    Scleros's Avatar
    Scleros Posts: 2,165, Reputation: 262
    Hardware Expert
    		  
    #2

    Jun 17, 2009, 07:58 PM
    Smells like homework. So...

    A 1 bit bus could address locations:
    0
    1
    or 2^1 = 2 locations.

    A 2 bit bus could address locations:
    00
    01
    10
    11
    or 2^2 = 4 locations.

    A 3 bit bus could address locations:
    000
    001
    010
    011
    100
    101
    110
    111
    or 2^3 = 8 locations

    See a pattern?
    natalie1xxx's Avatar
    natalie1xxx Posts: 120, Reputation: 3
    Junior Member
    		  
    #3

    Jun 18, 2009, 10:46 AM

    yeah , its doubling? :D
    so a 4 bit bus could address locations :
    0000
    0100
    0110
    0111
    0001
    0011
    0100
    0010
    1111
    1110
    1100
    1000
    1011
    1001
    1010
    1101
    = 16 :D
    Scleros's Avatar
    Scleros Posts: 2,165, Reputation: 262
    Hardware Expert
    		  
    #4

    Jun 18, 2009, 03:59 PM
    It's 2^(Number'o'Bits).
    natalie1xxx's Avatar
    natalie1xxx Posts: 120, Reputation: 3
    Junior Member
    		  
    #5

    Jun 18, 2009, 04:02 PM

    Whaaat? So is the answer I got not right ?
    Scleros's Avatar
    Scleros Posts: 2,165, Reputation: 262
    Hardware Expert
    		  
    #6

    Jun 21, 2009, 10:57 PM
    No it's right, I just giving general formula for any given number of bits.
    natalie1xxx's Avatar
    natalie1xxx Posts: 120, Reputation: 3
    Junior Member
    		  
    #7

    Jun 22, 2009, 12:06 PM

    Oh thanks :)
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