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    jamieelaurenn's Avatar
    jamieelaurenn Posts: 1, Reputation: 1
    New Member
    		  
    #1

    Jun 15, 2009, 05:00 PM
    Limiting reactants
    Identify the limiting reactant, the mass of each of the substances participating in the reation, and the mass or any remaining excess reactant.

    45g of iron(III) chloride pluse 65g of zinc yields zinc chloride pluse iron.
    LR______
    Iron(III) chloride______
    Zinc______
    Zinc chloride_______
    Iron_______
    Excess__________

    I have no clue how to do this, I can only get to this point:

    FeCl3 + Zn ---> ZnCl2 + Fe

    ... if it's even correct. I need HELPP!
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #2

    Jun 16, 2009, 07:54 AM

    You need a balanced equation, meaning that there should be the same number of moles of each atom or ion on both hand sides. You'll see that you have 3 Cl on the left, but only two on the right. Correct that first.

    Then, find the number of moles that is present in 45g of iron(III) chloride. You do that by dividing the given mass by the relative formula mass of iron(III) chloride. Find also the number of moles of Zn present by dividing the given mass by the relative atomic mass of the Zn.

    Through your equation, you'll have the ratio to which the reactants react. For example, if the ratio of moles of FeCl3 and Zn is 1:2, then you'll have one mole of FeCl3 reacting with 2 moles of Zn. If you have the number of moles of Zn greater than twice the number of moles of FeCl3, that means that the Zn is in excess and that the FeCl3 is limiting.

    To find the mass of the products, multiply the number of moles of each product to their relative masses.

    Hope it helped! :)

    Just post back if you need more details :)
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