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Junior Member
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Jun 7, 2009, 08:30 PM
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tan of pi/2
Am I mistaken but a question such as expand and simplify:
tan((pi/2)-y) and cot((3pi/2)+x) can't be done as tan of pi/2 and 3pi/2 are undefined? I got these questions out of a maths book with no solutions, could someone please verify this. Thanks in advance.
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Senior Member
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Jun 8, 2009, 06:01 AM
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Your instincts about the non-existence of the tan and cotan functions at certain argument values is pointing you in the right direction, and you'll be fine when you take it one step further.
Note that you've got a variable "inside" the argument in each case. Depending on what the variable's value is, it might move the whole argument off a "no-no" point before you hit the whole argument with the tan or cotan function.
Best of luck!
...it was early and I was full of no coffee...
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Senior Member
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Jun 8, 2009, 06:33 AM
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P.S. Also, double-check yourself on where the Cotan function is undefined.
...it was early and I was full of no coffee...
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Junior Member
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Jun 8, 2009, 08:11 AM
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Yep but if I use double angle formulas to expand to simplify I will end up separating the variables inside and it can' t be simplified :{
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New Member
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Oct 18, 2011, 02:24 AM
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Are you sure it can't be simplified?
tan((pi/2)-y) = sin((pi/2)-y)/cos((pi/2)-y) = (sin(pi/2)*cos(y)-cos(pi/2)*sin(y))/(cos(pi/2)*sin(y)+sin(pi/2)*sin(y))
now, you use the fact that sin and cos are defined in pi/2
sin(pi/2)=1
cos(pi/2)=0
so
tan((pi/2)-y) = cos(y)/sin(y) = cot(y)
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Uber Member
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Oct 18, 2011, 10:58 AM
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No you dropped the (pi/2 - y) for y, which makes the first and second in your equation unequal.
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New Member
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Oct 18, 2011, 11:07 AM
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What do you mean, Unknown008?
Just expanded by definitions of trigonometric functions and using the identity of the sin and cos of the sum of 2 angles, and then replace some values. Didn't "drop" any part of it.
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Uber Member
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Oct 18, 2011, 11:15 AM
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Oh, sorry, I was distracted and thought you put in sin(y)/cos(y).
Apologies :o
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