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Datsybb55 · Mar 30, 2009, 01:33 PM

72y2-98

Datsybb55 · Mar 30, 2009, 01:35 PM

determine the x-y-intercepts of the graph of each function y=x2-5xt4

galactus · Mar 31, 2009, 06:30 AM

Originally Posted by Datsybb55

72y2-98

I assume this is $72y^{2}-98$

First, note that if you divide 72 and 98 by 2, you have two perfect squares.

So, factor out a 2:

$2(36y^{2}-49)$

Now, see inside the parentheses? It is the difference of two squares.

I assume you know that factorization? It is, $x^{2}-y^{2}=(x+y)(x-y)$

Can you finish now? Let me know if you remain stuck.

galactus · Mar 31, 2009, 06:33 AM

Originally Posted by Datsybb55

determine the x-y-intercepts of the graph of each function y=x2-5xt4

What is this? Please do a preview before you post, so that you know it is displaying correctly or that you typed it correctly.

Is this it:

$y=x^{2}-5x+4$

If so, to find the x intercepts, then y must be equal to 0. Set y=o and solve for x bt factoring or using the quadratic formula.

For that matter, just graph it and look at the intercepts.

To find the y intercepts, set x=0.s an aside, just use ^ when you want an exponent.

Just writing x2 looks like you want to multiply x by 2.