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    nosher's Avatar
    nosher Posts: 2, Reputation: 1
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    #1

    Feb 13, 2009, 12:08 PM
    Force on an unequal see saw
    I would like to know how to work out the what the force would be on the longest end of an unequal see saw compared to the shorter sides force when one side of the see saw is 2 metres from the pivot point and the other side is 1 metre form the pivot point. There is a person on either end of the see saw weighting 50kg each
    rwinterton's Avatar
    rwinterton Posts: 289, Reputation: 15
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    #2

    Feb 14, 2009, 10:27 AM

    Use Torque: Torque = force * length of lever arm.
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