[selinaaa]

how do you solve inequalities with fractions? Such as 2/5 x -5>3?
I realllllllllllllly need help!

[ebaines]

Generally you can add and subtract to both sides of the inequality, just as if there was an equal sign rather than an inequality. You can also multiply and divide both sides by a factor, but if the factor is negative, you have to flip the inequality around.

So here you have 2/5 x - 5 >3

Add 5 to both sides:

2/5 x >8

Multiply through by 5/2:

x > 8*5/2,
x > 20.

Here's another example to illustrate what happens if you multiply through by a negative number:

5 - (2/5)x > 3

Subtract 5 from both sides:

-(2/5) x > -2
Multiply by -5/2, and remember to flip the inequality when you multiply by a negative number:

x < -2 (-5/2), or
x < 5

We could have done this a different way: starting again with

5 - (2/5)x > 3

Add (2/5)x to both sides:

5 > 3 +(2/5)x

Subtract 3 both sides:

2 > (2/5)x

Multiply through by 5/2 (since 5/2 is positive, you don't flip the inequality around):

2*5/2 > x, or
5 > x

This is the same as x< 5, so you see you get the same answer.

Hope this helps.