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    notamathwiz's Avatar
    notamathwiz Posts: 11, Reputation: 1
    New Member
    		  
    #1

    Aug 13, 2008, 06:41 AM
    Where to start?
    I am having a problem starting this question. I have tried 3 ways and every time I am getting the wrong answer.

    The problem is:

    Solve for X:

    10^2x-1=10^10

    For anyone who can help me start this I would really appreciate it. You are the best!
    galactus's Avatar
    galactus Posts: 2,271, Reputation: 282
    Ultra Member
    		  
    #2

    Aug 13, 2008, 07:20 AM
    Please use proper grouping symbols.

    Is it

    or



    I will assume the former:



    What is log(10)? That makes it easy.
    notamathwiz's Avatar
    notamathwiz Posts: 11, Reputation: 1
    New Member
    		  
    #3

    Aug 13, 2008, 07:29 AM
    Quote Originally Posted by galactus
    Please use proper grouping symbols.

    Is it

    or



    I will assume the former:



    What is log(10)?. That makes it easy.

    It is the former problem. Log (10) is 1. Thank you!
    notamathwiz's Avatar
    notamathwiz Posts: 11, Reputation: 1
    New Member
    		  
    #4

    Aug 13, 2008, 07:53 AM
    Quote Originally Posted by galactus
    Please use proper grouping symbols.

    Is it

    or



    I will assume the former:



    What is log(10)?. That makes it easy.
    I am assuming I would take it from there in by doing:

    (2x-1) log(10)=10log(10)

    2x-1 = 10

    2x = 11

    11/2

    and that's what x = or 5 1/2
    Rehaan_genius's Avatar
    Rehaan_genius Posts: 49, Reputation: 1
    Junior Member
    		  
    #5

    Aug 13, 2008, 08:00 AM
    Hey dude! You got it right. 5 1/2 is 11/2! I think you are asking this,huh?
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