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    mrs_vick's Avatar
    mrs_vick Posts: 7, Reputation: 1
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    #1

    Feb 13, 2006, 08:30 PM
    Algebra Ii (elimination & Substitution)
    solve by elemination

    {x + y = 10
    x - y = 2
    solve by substitution

    y = x +1
    2x + y = 7



    :eek:
    happybisaya's Avatar
    happybisaya Posts: 68, Reputation: 6
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    #2

    Feb 14, 2006, 07:03 AM
    -------IGNORE THE DOTS, I USED IT FOR PROPER SPACING------
    For elimination, simply add the two equations.
    x + y = 10
    x - y = 2
    _________
    2x... = 12
    2x/2.. = 12/2
    ... x=6

    Choose one of the equation to solve for (y) and plug 6 instead of an (x).
    6 + y = 10
    -6... -6
    __________
    ... y = 4
    Your answer should look like this: (6,4)-- this is where the two lines intersect.


    For substitution, plug y= x + 1 into the second equation 2x + y = 7.
    2x + (x+1) = 7
    2x + x + 1 = 7
    3x + 1 = 7
    ... - 1... -1
    _____________
    3x... = 6
    3x/3... = 6/3
    ... x = 2 ------- now choose one of the equation (any one of the two), and use (2) instead of an (x).

    let us use y = x + 1
    y = 2 + 1
    y = 3 ----- this is your (y)

    your answer is (2,3)
    LebaneseAngel33's Avatar
    LebaneseAngel33 Posts: 1, Reputation: 1
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    #3

    Dec 17, 2008, 10:48 AM
    Comment on happybisaya's post
    A lot of help !
    jeric20's Avatar
    jeric20 Posts: 2, Reputation: 1
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    #4

    Oct 9, 2009, 04:31 AM
    Exampls of elimination by substitution
    jeric20's Avatar
    jeric20 Posts: 2, Reputation: 1
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    #5

    Oct 9, 2009, 04:32 AM

    x+y=7
    Perito's Avatar
    Perito Posts: 3,139, Reputation: 150
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    #6

    Oct 9, 2009, 09:01 AM
    Quote Originally Posted by jeric20 View Post
    exampls of elimination by substitution
    Pick any two independent equations.

    X = Y + 45
    Y = 49

    They're usually more complicated that this, but this serves the purpose.

    Substitute "49" everywhere you see "Y"

    X = 49 + 45

    You then solve for X. That's substitution.
    dh664's Avatar
    dh664 Posts: 3, Reputation: 1
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    #7

    Apr 9, 2010, 10:04 PM

    x+y=10
    x-y=2

    2x=12
    x=6

    6+y=10
    y=4
    (6,4)


    y=x-1
    2x+y=7

    2x+x+1=7
    3x+1=7
    3x=6
    x=2

    2(2)+y=7
    4+y=7
    y=3
    (2,3)
    iandloveandyou's Avatar
    iandloveandyou Posts: 1, Reputation: 1
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    #8

    Jan 8, 2011, 10:07 PM
    x+y+0
    x+y+4
    nidie_anne's Avatar
    nidie_anne Posts: 1, Reputation: 1
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    #9

    Mar 9, 2011, 05:21 AM
    elimination:
    x+y=10 x+y=10 x+y=10
    x-y=2 -(x+y=2)- -x+y=-2

    2y=10-2
    2y=8/2
    y=4
    subtitution:
    y=x+1 2x+(x+1)=7
    2x+y7 (2x+x)+(1=7) 3x=7-1 3x=6/3 x=2
    2x+y=7

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