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    McNuggy@LMC's Avatar
    McNuggy@LMC Posts: 40, Reputation: 3
    Junior Member
     
    #1

    Feb 13, 2006, 02:26 AM
    linear equations... finding the value of a straight line
    hi there... can you answer this for me please.

    or even give a better layman understanding of how to interprete the formula.

    the equation is

    y-y1=m(x-x1) ------ (1,2) gradient 3


    is m the gradient or is x1 the gradient

    arrrgh I`m trying to help my little brother here and its hard because the book is not in front of me, that said I`m not the best at algebra or math really. I do have a little bit of memory from school but considering it was 11 years ago its kind of blurry
    thanks for any help you can give me
    happybisaya's Avatar
    happybisaya Posts: 68, Reputation: 6
    Junior Member
     
    #2

    Feb 13, 2006, 02:06 PM
    formula: y-y1 = m(x-x1)
    point: (1,2)
    slope: 3

    y-2 = 3(x-1)
    y-2 =3x-3
    +2 +2
    _________
    y = 3x-1 ------ Answer; equation of the line
    happybisaya's Avatar
    happybisaya Posts: 68, Reputation: 6
    Junior Member
     
    #3

    Feb 13, 2006, 02:10 PM
    Oh I forgot to answer your other question. 3 is your gradient or slope.
    McNuggy@LMC's Avatar
    McNuggy@LMC Posts: 40, Reputation: 3
    Junior Member
     
    #4

    Feb 19, 2006, 04:39 PM
    Thank you very much mr happy... I`m still in the dark but my little brother has figured it out and he also thanks you for your reply. Cheers:) :) :)
    happybisaya's Avatar
    happybisaya Posts: 68, Reputation: 6
    Junior Member
     
    #5

    Feb 19, 2006, 05:33 PM
    Quote Originally Posted by McNuggy@LMC
    thankyou very much mr happy..... i`m still in the dark but my little brother has figured it out and he also thanks you for your reply. cheers:) :) :)
    You are welcome.

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