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bobbyshores · Jan 30, 2011, 08:23 PM

(1/sec(x)tan(x))+ sin(x)

and

cot^2(x)+cot^2(x)Tan^2(x)

galactus · Jan 31, 2011, 03:45 AM

What are you supposed to do with those?

I do not see an equation.

Taking a guess, the last one can be simplified:

Factor out $cot^{2}(x)$ :

$cot^{2}(x)(1+tan^{2}(x))$

Note what is in the parentheses is an identity, $sec^{2}(x)=1+tan^{2}(x)$ .

So, we have:

$cot^{2}(x)sec^{2}(x)$

$\frac{1}{tan^{2}(x)cos^{2}(x)}$

But, by using $\frac{sin(x)}{cos(x)}=tan(x)$ , we can see that the denominator is equal to:

$\frac{1}{sin^{2}(x)}$

$=csc^{2}(x)$