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missgeek · Feb 3, 2010, 07:02 PM

Any help with this would be much appreciated.

galactus · Feb 4, 2010, 09:57 AM

$1-\frac{2}{x}=\frac{2}{x+2}$

Is this what is meant?

If so, multiply both sides by x(x+2) to eliminate the fraction.

$x(x+2)-\not{x}(x+2)\cdot \frac{2}{\not{x}}=x\not{(x+2)}\cdot \frac{2}{\not{x+2}}$

$x^{2}+2x-2x-4=2x$

See? The fraction is eliminated by multiplying through by the LCD,
x(x+2)

missgeek · Feb 4, 2010, 05:24 PM

Thank you, I worked through it and I got the same answear and I contiued working through.
Was I right to use the quadratic formula next I ended up with 3.7 and .27

galactus · Feb 5, 2010, 05:23 AM

The problem said to keep it in simplest radical form. Do not write it as a decimal but as $\sqrt{5}+1, \;\ -\sqrt{5}+1$