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So, I've been looking for a car and I came across a 1989 chevy camaro for 800$. It's missing a fuel pump and a gas tank and has 68,000 miles on it. My question is, since the mile counter resets after...

I got 1069.26m, which is wrong. I tried finding the velocity for 1 and 2 with the first equation, and then found the distance and added them together. But it didn't work.

Ahh, thanks, the negaive displacement was the problem. I got it now. :)

I know what distance and displacement are, and I'm 99.9% sure I got this question right, but for my physics class we have to submit our answers online and it keeps marking me wrong for this one. I...

A record of travel along a straigt path is as follows:
a) Start from rest with constant acceleration of 3.06m/s2 for 19.8s;

b) Constant velocty for the next .845 min;

c) Constant negative...

While john is traveling along a straight interstate highway, he notices that the mile marker reads 252km. He travels until he reaches the 149km marker and then retraces his path to the 168km marker....

Thanks! This website is awesome! :D

Thanks!

An acceleration of 5.6 mi/h/s is equal to what in units of m/s2?

Please explain what and why.

[QUOTE=Unknown008;1977830] You see, the sum of the initial and final velocities when divided by two cannot be added to a displacement.
QUOTE]

Why not?

When calculating for final displacement, what is the difference between these two equations?

1. x(f) = x(o) + V(o)t + at2 / 2


2. x(f) = x(o) + (v+v(o)) / 2

...