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Assuming the road is level, the force slowing the car down is given by
F = mu*N
where mu = 0.710, and since the road is level, N is the weight, m*g.

That force will cause acceleration...

One other thing to consider. The ball has another force on it that consumes its energy. Drag. If you had a ball with neutral buoyancy, it would slow down from drag in the water. And finally come to a...

I agree with jiten55. It turns out that the force of friction is the same whether one is sitting on the other or if they are both sitting on the surface. You might quibble and say the way the...

Where is the valve? Between the right and left ends of the tube perhaps? What is the on the far side of the valve?

I guess I didn't give you all the steps. I tried these just now and they worked.

I'll revise my advice:
c. You could calculate vertical velocity and horizontal velocity separately using
Vf^2 =...

If you just used a straight rod, and held it in your hand, your hand would damp out the vibrations. A tuning fork has a handle you can hold without disrupting the vibrations. I think there may be...

a. You can ignore the horizontal wind. Any horizontal speed it picks up doesn't change the increasing vertical speed.
y = Vo*t + (1/2)*g*t^2
where Vo = 0 and g = 9.8 m/s^2. Solve for t.

b. Hmmm....

a. Determine the acceleration.
F = m*a

To find distance use
x = Vo*t + (1/2)*a*t^2
where Vo = 0

b. Determine the acceleration (the mass is higher now). Everything else is done the same as...

This looks like a trick question aimed at measuring your confusion. If you disregard air resistance, the only force on it is the weight. So the answer to both a. and b. is

W = m*g = 0.150 kg*9.8...

And for part (a) you can use
x = (Vo + Vf)*t/2
where x is distance, Vo is original velocity, Vf is final velocity, and t is time - your unknown. Note: (Vo + Vf)/2 is average velocity, so when you...

I have to disagree with the 1st post. That one assumes that there is no increase in speed from coming down the hill.

Best to use conservation of energy, in fact that was the subject you gave the...

"rock dropped in water in term of its speed and acceleration": Assume you held the rock at the surface so the rock was fully submerged, and then released it. The rock has weight. That's a force....