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If you have the sums $ (1+2+.. +n) + (1+2+3+.. +n-1)+ (1+2+3+.. +n-2)+(1+2+3+.. +n-3)+... +(1+2+3)+(1+2)+1$ for large enough $n$
$$\frac {n^3}{3!} \approx (1+2+.. +n) + (1+2+3+.. +n-1)+ (1+2+3+.....

If \delta=\frac 1m then
\frac{n(n+\delta)(2n+\delta)}{6}=\frac1{m^3}\frac{mn(mn+1)(2mn+1)}{6}=\frac1{m^3}\sum_{k=1}^{mn}k^2=\frac1{m}\sum_{k=1}^{mn}\left(\frac km\right)^2.

We get *in the...

If you have the sums $ (1+2+.. +n) + (1+2+3+.. +n-1)+ (1+2+3+.. +n-2)+(1+2+3+.. +n-3)+... +(1+2+3)+(1+2)+1$for large enough $n$
$$\frac {n^3}{3!} \approx (1+2+.. +n) + (1+2+3+.. +n-1)+ (1+2+3+.....

if have well-known (jednacinu) equation ((n 1) * n) / 2 = 1 2.. n. Now if the difference between the closest numbers smaller, to get ((n 0,1) * n) / (2 * 0,1) = 0,1 0,2.. n. If the...

Napravio sam gresku u gornjem komentaru mislio sam na jednakokraki trougao, ne na jednakostranicni trougao

ideja oko normalne proekcije tacke sa kruznice na poluprecnik, gde ja odnos te, tacke / njene proekcije na radius = precnik / tetive (mat pojam) paralelne sa tom tackom. Ima za posledicu mnogo...

if (in circle) angle AS < 180, and angle AS = 2 angle AD = 4 angle AF, so (chord AS - (2 chord AD)) * (diameter / 8) = triangle AFD, triangle AFD * 4/3 ~ segment of a circle AD, so if chord AD =...

if diameter is 10, for example : (5 / (10 / 8,6602.. )) + (( 5 - (5 / (10 / 8,6602.. ))) * 4/3) = 5,223.. ~ 5,23333...

That image is correct, an explanation should be fine

Explain this formula (it is very difficult, and not so important): (opposite AB / sec) + ((opposite AB - (opposite AB / sec)) * 4/3) ~ arc AB : Whether this formula can be write in a different way?

Now l realize that you are the expert not only in math but also psychiatry (lucky for you). This formula is correct (easily verifiable) so can not be crazy, to which you do not understand, l will...

or (7,85 - 7,071.. ) * (10 / 8) = 0,97375

no, if diameter is 10 ; (15,7 - 10) * (10 / 8) = 7,125 cm 2

explain formula : (minor arc (AB) - chord (AB)) * (diameter / 8) = segment of a circle (minor arc (AB) / 2)

Sustina je da, kada od povrsine polukruga oduzmes pravougli trougao ciji je poluprecnik jednak hipotenuzi, dobices povrsinu dva segments, e sada kada bi oduzeo sve moguce pravougle trouglove od...

OK , pokusacu da objasnim , nacrtaj cetvrtinu kruga, sada zamisli da je centralna tacka povezana poluprecnicima (radius you mnozini) sa svakom tackom na cetvrtini kruznice, na taj nacin dobio bi...

2 pi 2 / (pi 2 - 4) je formula koja daje odnos zbira povrsina svih jedinstvenih segments (pi 2 - 4) I zbira odgovarajuceg broja povrsina circle (2 pi 2), odnosno volume of a cylinder I volume...

pod uslovom da je hipotenuza = precnik

Serb : ako mozes da razumes zasto je (opposite AB / sec) + ((opposite AB - (opposite AB / sec)) * 4/3) ~ arc AB mozda I mo nadjes poentu u gornjim jednacinama

serb : V = pi * r ^ 2 * h / 3,3629.. A = pi * r ^ 2 + pi * r * h su obrasci koji definisu jednu geometrisku figuru ( koja nije valjak) to jest njenu zapreminu I povrsinu a pitanje je koja je to...

surface area = pi * r 2 + r * pi * h for this figura

Serb language moj engleski jezik je slab, I u pitanju sam mislio na krug a ne na valjak, moja greska ali hvala na odgovoru

Translated: serb language my english is poor, and I thought about the...

Serb language. Moj engleski je slab, mislio sam na krug ali tenks for answer

Translated: serb language. My English is bad, I thought the round but tenks for answer

No is not,l give my anwers

2 pi 2 / ((pi 2) - 4) = 3,3629...

OK, mlad si, razumi ovo kao neki zadatak I ako mozes resi ga, srecno, vise necu davati komentare

Koliko imas godina

Pa Srbi su pametan narod I to nije formula za zapreminu cilindra vec za drugaciju geometrisku figuru,

I'm serb

Is volume formula, not for cylinder

No is not