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I got it for the second one, and thank you :)

For the first one:
Since it takes care of the combined charges, you would have twice the charge of the protons. I'm seeing it like this: first charge...

But don't you require more work since there is an effect of combined charges? (the two protons)

You mean I don't add up the charges? Do you have the reason as to why? I simply cannot understand that clearly :(

Qu:
The two protons of a helium nucleus are about 1.5\times 10^{-15}\, m apart. Find the electrostatic force between them. How much work must be done against this force in bringing two protons from...