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Type: Posts; User: cari1966

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  1. Answers
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    2,437

    Thank you...

    Thank you...
  2. Answers
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    2,437

    so it P(E|F)= .23/.6 AND P(F|E)= .23/.40?

    so it P(E|F)= .23/.6 AND P(F|E)= .23/.40?
  3. Answers
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    2,437

    I have the formula E|F=p(E AND F)/pF but I don't...

    I have the formula E|F=p(E AND F)/pF but I don't get how to work it.
  4. Answers
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    2,437

    Compute P(E|F) AND P(F|E)

    Compute P(E|F) AND P(F|E) GIVEN P(E)=.4 P(F)=.6 AND P(E AND F)= .23
  5. Answers
    8
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    2,437

    Compute P(E|F) AND P(F|E)

    Compute P(E|F) AND P(F|E) GIVEN P(E)=.4 P(F)=.6 AND P(E AND F)= .23
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    3,314

    I left out the f={1,11,21}. So would the answer...

    I left out the f={1,11,21}. So would the answer be 21,26 or does it mean included in all E,F,G which would be none,because there is none that are in each one?
  7. Answers
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    3,314

    find the probabilty events

    Let s={1,6,11,16,21,26}, E={6,16,26}, and G={21,26} Find the event E F AND G. Upside down u in between each letter. If there are no elements in the set, enter NONE
  8. how to solve the probability of something occurring given that it isn't

    a wallet contains 8 $1 bills, 3 $5 bills and 8 $10 bills. A bill is selected at random from the wallet. Find themprobability of the following


    a. the bill is a $1, given that it is smaller...
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