Ask Experts Questions for FREE Help !
Ask
    Celine.marquis's Avatar
    Celine.marquis Posts: 1, Reputation: 1
    New Member
    		  
    #1

    Nov 9, 2010, 10:39 AM
    limiting reactants
    what is the limiting reactant in 2KI Pb(NO3)2
    my balanced equation looks like this;
    2KI Pb(NO3)2-> 2K(NO3)2=PbI2
    but I need to find the limiting reactant, we used 1gram of KI and 1gram of the Pb(NO3)2
    totally lost
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
    Uber Member
    		  
    #2

    Nov 9, 2010, 11:07 AM

    Find how many moles of each reactant you have.

    From your balanced equation, find the mole ratio between the reactants.

    From there, you should be able to guess deduce which reactant is limiting.
Not your question? Ask your question View similar questions
 

Question Tools Search this Question
Search this Question:

Advanced Search

Add your answer here.


Check out some similar questions!

Chemistry Reactants? [ 7 Answers ]

N2(g) + 3H2(g) 2NH3(g) + 100.4 kJ A yield of NH3 of approximately 98% can be obtained at 200o C and 1,000 atmospheres of pressure. What is the H in kJ of heat released per mole of NH3(g) formed? How many grams of N2 must react to form 1.7 grams of ammonia, NH3?

Limiting reactants [ 1 Answers ]

Identify the limiting reactant, the mass of each of the substances participating in the reation, and the mass or any remaining excess reactant. 45g of iron(III) chloride pluse 65g of zinc yields zinc chloride pluse iron. LR______ Iron(III) chloride______ Zinc______ Zinc chloride_______...

Products and reactants [ 1 Answers ]

What r the reactants and products of photosynthesis??

Reactants with photosynthesis [ 1 Answers ]

What are the reactants that plants use to photosynthesise?:confused:

Limiting Reactants [ 2 Answers ]

Can you tell me if I did this right Mg + I2 -> MgI2 identify the limiting reactants A) 100 atoms of Mg and 100 molecules of I2 100 atoms Mg* 1mol/6.02E32 * 24g Mg/ 1 mol =3.99E-21g Mg 100 molecules I2 * 1 mol/6.02E23 * 258g I2/ 1 mol = 4.28E-20g I2 3.99E-21g Mg * 1mol/ 24g Mg * 1mol...

View more questions Search