The length of a simple pendulum is 0.760m the pendulum bob has a mass of 365g and it is released at an angle of 12.0 degres to the vertical. a) With what frequency does it vibrate? Assume SHM. b) what is the pendulum bob's speed when it passes through the lowest point of the weing? c) What is the total energy stored in this ocillation assuming no losses?

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If L is the length, A the amplitude, and S the distance from the lowest point, and X (Radians) the given angle, then Velocity V is given by:

V^2 = g/L (A^2 - S^2)

In this case, A = LX (Length of arc from highest to lowest point)

So you have got value of A

VELOCITY AT LOWEST POINT:

You need value of V when S = 0

Above equation then becomes: V^2 = g/L A^2

V = A times Square root of (g/L)

FREQUENCY

Formula for Period is :

T = 2 pi (L/g)^.5

Frequency = 1/T

ENERGY

At the lowest point, we found

V^2 = g/L A^2

Hence Energy at the lowest point (m = mass)

= Kinetic Energy

= 1/2 mV^2 = 1/2 mg/L A^2

This is the Energy stored.