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    VishalManu's Avatar
    VishalManu Posts: 7, Reputation: 1
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    #1

    Jul 9, 2012, 11:44 PM
    Calculation of pressure developed in a uniformly charged spherical shell
    I went about calculating the pressure developed in a uniformly charged spherical shell like this
    consider an infinitesimal area dA on the surface of the shell with a charge density of 's'.
    Charge on the area is q=s*dA
    from gauss law the electric field at the surface(perpendicular to the surface always)= s/eps0
    force on the area= E*q=s^2*dA/eps0
    pressure= F/dA=s^2/eps0

    I think I am missing a factor of 1/2.

    Can someone tell me the mistake?
    Thanks a lot
    pianobuggy's Avatar
    pianobuggy Posts: 3, Reputation: 1
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    #2

    Aug 9, 2012, 05:00 PM
    Probably comes from double-counting the charges. Have you tried looking at this from an energy perspective? What is dV/dr, when V is the potential for a small charge on the sphere as a function of radius. -qdV/dR=force.

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