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    babi_gurl's Avatar
    babi_gurl Posts: 30, Reputation: 2
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    #1

    Feb 25, 2007, 04:38 AM
    Constant acceleration
    ;) hiii I realli need help with the below question...
    A bullet passes through a board, the velocity on entering being 1200 m/s and on leaving 1100m/s. how many such boards of equal thickness placed one behind the other will the bullet penetrate assuming constant retardation.
    :confused:
    Thanks :o
    Capuchin's Avatar
    Capuchin Posts: 5,255, Reputation: 656
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    #2

    Feb 25, 2007, 04:47 AM
    One borad slows it by 100m/s, so how many boards will slow it by 1200m/s?
    Capuchin's Avatar
    Capuchin Posts: 5,255, Reputation: 656
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    #3

    Feb 25, 2007, 05:17 AM
    Received in PM:
    Quote Originally Posted by babi_gurl
    huh i still dont get...like how are we supposed to find out how many boards will the bullet penetrate....
    Each board will slow it by a further 100m/s...
    The first board slows it to 1100m/s
    The second slows it by another 100m/s to 1000m/s
    The third slows it to 900m/s

    How many boards slow it to 0m/s?
    Capuchin's Avatar
    Capuchin Posts: 5,255, Reputation: 656
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    #4

    Feb 25, 2007, 05:30 AM
    Received in PM:
    Quote Originally Posted by babi_gurl
    ohkk i see.. can we use an arithmetic progression equation .. Tn= a+(n-1)d where a=1100 and the difference, d, = -100 to find how many boards would penetrate
    Or you could just divide 1200 by 100...

    Could you please stop talking in PM?
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