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    Aiyume's Avatar
    Aiyume Posts: 14, Reputation: 1
    New Member
    		  
    #1

    Oct 7, 2010, 07:52 PM
    Force, Torque
    A claw hammer is used to pry up a nail. Approximately how much force is applied to the nail when a force of 100 N is applied at an angle of 90 degrees to the end of the 35.2 cm long straight handle of the hammer?

    Since I don't know how to upload the diagram, I will try to describ it.
    There is a downward force 100N where you hold the hammer. Nail has has an upward force, F.
    The pivot point is somewhere along the hammer, O. The distance from O to the nail is X.

    Calculation:
    Sum of [T] = 0
    (100) (-35.2/100 ) + FX = 0
    F = 35.2/X

    Is this correct?
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #2

    Oct 8, 2010, 01:00 AM

    It seems correct to me. :)
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