[Rinka]

;D
Sorry if I sound very stupid...

A golfer hits a golf ball of mass 51g and the ball leaves the club with a velocity of 80m/s. Assuming that the ball and club are in contact for 0.0006s, find the ball's final momentum and the average force exerted by the club on the ball

Next :
diver dive from a height of 36m into the sea. Mass = 61kg.
In a free-fall, before parachute is opened, diver reach terminal speed of 90m/s.
Calculate force of air resistance on the diver when terminal speed

:-[


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Velocity vs time graph
A overtakes b t=0
B accelerates and overtakes A
What is the maximum distance between the cars before B catches up with A

Why is it that part of the graph, (with dots)
where both lines intersect
I don't understand... can someone please explain??
AHHH! Thank you
:'(

[Dr._Ephemeron]

A.)

F_avg*delta_t = m*v_t - m*v₀

v₀ = 0

delta_t = 0.0006 s

m = 51E-3 kg

v_t = 80 m/s

F_avg = 51E-3*80/0.0006 = 6800 N

p = m*v_t = 51E-3*80 = 4.08 kg*m/s

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B.)

SUM OF THE FORCES = MASS x ACCELERATION

do a free body diagram of the sky diver with all the forces acting on him. He is at a terminal velocity so he is moving at a constant velocity. This means that the forces are equal all around him because he is not accelerating anymore.

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C.)

I don't understand your graph but for constant acceleration:

x = x₀ + v₀*t + 1/2*a*t²

you want to set the equations for each moving object equal to the same point on the graph. You should be able to do that at 2 points giving you a system of 2 equations with 2 unknows.