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A ball is thrown straight up from the surface of the earth with an initial speed of 15.7 m/s. Neglecting any effects due to air resistance, what is the magnitude of the ball's displacement (from the starting point) after 0.60 s has elapsed?
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The velocity as a function of time for an asteroid in the asteroid belt is given by v(t)= v0e^(t/t0) I + v0t/2t0 j with vo and to constants. Use ti = 0 as the initial time, and tf = 1.5 to as the final time. The values for the constants that you will use are: vo = 4.5 m/s View more questions Search
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