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    kero's Avatar
    kero Posts: 12, Reputation: 1
    New Member
    		  
    #1

    Nov 6, 2009, 09:57 PM
    Momentum collision
    A pendulum bob of mass 10m and length L is pulled back to a horizontal position and released from rest. At the bottom of its path the bob collides wit perfect elastically with a ball of mass m originally at rest and a height "h=L" above the floor. Given L determine:
    a.the speed of the 10m mass before the collision.
    b. the speed and direction of the 10m mass just after the collision.
    c. the speed of the ball just after the collision.
    d. the horizontal distance the ball travels before hitting the ground.
    e. the maximum angle the 10m swings to after the collision.


    For part a, I get 2√gL
    the momentum equation:
    10mva0=10mva+10mvb
    v=va-vb
    but I keep getting zero for the speed and don't know how to solve the rest:confused:
    hope you guys can help:o
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
    Uber Member
    		  
    #2

    Nov 7, 2009, 06:55 AM

    Lol, you did a slight mistake there. The mass of the ball is 'm' and not '10m'. Can you get the others now? :)
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