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susus · Dec 10, 2010, 02:45 PM

so again, I'm updating my question:

The figure shows a mass M inside a tube bent in a circle of radius R=1.50 m. M can slide with negligible friction inside the tube. The tube rotates about a vertical axis passing through the center. The mass is in equilibrium at θ =43.5 degrees. Calculate the number of revolution the hoop makes in 10.0 s.
so I got 4.78

Now my problem is with this :
Calculate the linear speed of the mass at that equilibrium location.
(in m/s)

here is it's picture
http://i49.tinypic.com/2cr845u.jpg

ebaines · Dec 10, 2010, 03:14 PM

susus - it's better to ask a follow-up question in the same thread as before, rather than starting a new thread. From that previous thread (here: https://www.askmehelpdesk.com/physic...be-533066.html ), the linear speed of the mass is the tube rotates is:

$<br /> v = r\omega<br />$

and for this problem

$<br /> r = R\sin \theta<br />$

You already know $\omega$ and $\theta$ , so what's the problem?

susus · Dec 11, 2010, 07:44 AM

I just did not know how to update the question

Unknown008 · Dec 12, 2010, 10:35 AM

Next time, just reply in the 'answer box'. The 'reply' button has a limited number of characters, so, it might be better in all cases to use the 'answer box'.

susus · Dec 12, 2010, 01:42 PM

OK I did it , thanks