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    xgreeneyes98x's Avatar
    xgreeneyes98x Posts: 2, Reputation: 1
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    #1

    Oct 10, 2007, 06:19 PM
    Kinetics- Acceleration of a Vertical Ball
    A ball thrown vertically upward is caught by the thrower after 25 seconds. Find the initial velocity of the ball and the maximum height it reaches.
    terryg752's Avatar
    terryg752 Posts: 197, Reputation: 4
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    #2

    Oct 11, 2007, 03:31 AM
    initial velocity = u, distance = s = 0 when ball comes back, t = time = 25, acceleration = g = - 32ft/sec

    s = ut + 1/2 gt^2 (By t^2 I mean square of t)

    0 = 25 u - 16 25^2,

    u = 400 ft/sec = Initial velocity

    For the second part:

    u = 400, acceleration a = -g = -32, v = final velocity = 0

    Formula: v^2 -u^2 = 2as

    -400^2 = -64s

    s = 2500 ft.

    Height = 2500 ft
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