Roddilla - we are not going to take your exam for you! I suggest you work through each step of the problem, and if you get stuck along the way please show us what you tried and how you got stuck - then we can help point the way.

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Your value for Young's Modulus should not have a negative sign in the exponent. It should be on the order of the reciprocal of what you got. What did you calculate for the stress and elongation?

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Your value for Young's Modulus should not have a negative sign in the exponent. It should be on the order of the reciprocal of what you got. What did you calculate for the stress and elongation?

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That seems just about right. I get the same answer if I round the extension up to 0.08, but I would suggest you keep at least one more significant digit.

Jerry, how different was your answer? I think I'm right, but I must admit I'm not entirely sure if I'm off by a factor of two. You've probably done this sort of problem much more recently than I have! ;)

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JC: I Think you're correct. I'm getting E=2.45 x 10^11 Pa, or 245 GPa. By the way, Young's Modulus for steel is on the order of 200 GPa (depending on the particular alloy), so this seems reasonable.

I calculate a stress of 18.8 GPa and strain of 7.7%.

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JC: I Think you're correct. I'm getting E=2.45 x 10^11 Pa, or 245 GPa. By the way, Young's Modulus for steel is on the order of 200 GPa (depending on the particular alloy), so this seems reasonable.

I calculate a stress of 18.8 GPa and strain of 7.7%.

So for the force which is extending the wire you take the tension of each half of the wire
My teacher is saying that in order to calculate extension you have to use the tension of one half of the wire only which surely doesn't make sense

Could you plase post the working of the question so that I can compare it to mine

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So for the force which is extending the wire you take the tension of each half of the wire
My teacher is saying that in order to calculate extension you have to use the tension of one half of the wire only which surely doesn't make sense

OK, now I'm embarrassed. I'm afraid I forgot to divide by 2 and I'm off by a factor of 2.

From the symmetry of the problem you can see that half of the 175N is carried by each half of the wire. So the tension in the wire is found from:

So T = 235.6N, and Stress = 235N/(.025 mm^2) x 10^6 mm^2/m^2 = 9.42 x 10^9 Pa

Strain is 7.7%, so

E = Stress/Strain = 9.42 x 10^9 Pa/0.077 = 122 GPa.

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EB, that was exactly the factor of two I was unsure about. In fact, that was my first way of calculating it, but then I looked up the Young's Modulus of steel (and saw Rodilla's answer) and decided it must be wrong.

I definitely agree with your answer now though. And the fact that it's low compared to the book value for E is not surprising since the wire is assumed to have gone beyond its elastic limit.

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EB, that was exactly the factor of two I was unsure about. In fact, that was my first way of calculating it, but then I looked up the Young's Modulus of steel (and saw Rodilla's answer) and decided it must be wrong.

I definitely agree with your answer now though. And the fact that it's low compared to the book value for E is not surprising since the wire is assumed to have gone beyond its elastic limit.

But if two tensions are acting from the centre, why don't you take the force acting on the wire as 235 x 2?

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EB, that was exactly the factor of two I was unsure about. In fact, that was my first way of calculating it, but then I looked up the Young's Modulus of steel (and saw Rodilla's answer) and decided it must be wrong.

I definitely agree with your answer now though. And the fact that it's low compared to the book value for E is not surprising since the wire is assumed to have gone beyond its elastic limit.

In my opinion it is like 1 half of the wore is receiving 236N of force while the other half is also receiving 236N of force so the total length of the wore is receiving 236*2

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EB, that was exactly the factor of two I was unsure about. In fact, that was my first way of calculating it, but then I looked up the Young's Modulus of steel (and saw Rodilla's answer) and decided it must be wrong.

I definitely agree with your answer now though. And the fact that it's low compared to the book value for E is not surprising since the wire is assumed to have gone beyond its elastic limit.

If you take 236N only then you must take one half of the wire only, no?

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So for the force which is extending the wire you take the tension of each half of the wire
My teacher is saying that in order to calculate extension you have to use the tension of one half of the wire only which surely doesn't make sense

OK, now I'm embarrassed. I'm afraid I forgot to divide by 2 and I'm off by a factor of 2.

From the symmetry of the problem you can see that half of the 175N is carried by each half of the wire. So the tension in the wire is found from:

So T = 235.6N, and Stress = 235N/(.025 mm^2) x 10^6 mm^2/m^2 = 9.42 x 10^9 Pa

Strain is 7.7%, so

E = Stress/Strain = 9.42 x 10^9 Pa/0.077 = 122 GPa.

Sorry for the previous error.

Why do you divide by two if the every tension is acting on a half of the string?

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I got 1.22338... × 10^11 and saw the same thing on the screen... =/

Okay Rodilla, for your comments now (please, use the answer box below the page instead of using the comments options please.

In my opinion it is like 1 half of the wore is receiving 236N of force while the other half is also receiving 236N of force so the total length of the wore is receiving 236*2

No, if you use the whole wire and double the extension the tension that you use has to be the same.

If you take 236N only then you must take one half of the wire only, no?

As per above, you take 236 N when taking the whole wire too.

why do you divide by two if the every tension is acting on a half of the string?

The tension is divided by two because the portion of the wire that he is working with is half the total length of the wire.

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SO as you are saying unknown008 the answer would still come to be 2 * 10^11 approximately since total extension of wire is 0.008, the original length is 0.10, the total force acting on the whole wire is 236 * 2 and the area is 2.5 * 10^-8
E = 1.89 * 10^10 (stress) * 0.10/0.008 = 2.36 * 10^11

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SO as you are saying unknown008 the answer would still come to be 2 * 10^11 approximately since total extension of wire is 0.008, the original length is 0.10, the total force acting on the whole wire is 236 * 2 and the area is 2.5 * 10^-8
E = 1.89 * 10^10 (stress) * 0.10/0.008 = 2.36 * 10^11

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