A cannon sends a projectile towards a target
A distance 1590 m away. The initial velocity
Makes an angle 40◦ with the horizontal. The
Target is hit. How high is the highest point of the trajec-
Tory?

Here's the method to use:

1. Set up the equation for the horizontal compomnent of motion:



where is the initial veocity of the projectile out of the cannon and is the time it taks to reach the target.

2. The equation for the vertical component of motion is:



3. Now you have two equations in two unknowns, and you need to solve for t. Then determine the value for y at time t/2.

Post back with what you get for an answer.