Melron2 Posts: 1, Reputation: 1 New Member #1 Oct 3, 2013, 05:46 PM
Math
After reading a copy of the play Hilda wants the part that has twice as many lines as the part of Betty, Adam has chosen a part that has three more than twice as many lines as the part that Hilda wants . Renean will try out for the part with four more lines then Betty's part. If they get the parts they want togetherness hey will have a total of 47 speaking lines . How many lines will each actor have in the play?
 15yearoldgirl Posts: 49, Reputation: 5 Junior Member #2 Nov 9, 2013, 04:49 PM
Betty = 5
Hilda = 10
Renean = 9

5+10+23+9 =47

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