If csc C = 3 and side b=6cm in right triangle BAC.
Answer should be 6 + 6(sqrt2) but I'm not sure how to get there.
Thanks

If you have a Right angle that goes up 3', and across 4', and want to find the length of the angled side. You would square the 3, which is 9. The square the 4, which is 16. Then add the two, 9+16=25, Now find the square root of 25, you get 5, which the 3 side is 5. This 3,4,5. Or 6,8,10 is commonly used to see if something is square.
In construction you make 1 mark 3 foot from corner, then 4 feet from same corner other way, Now when you measure between these 2 marks you should have 5, if not, Form boards needs to be tweeked until it equals 5 to be square. 6,8, 10 is more accurate. And on very large, you could do 60, 80, 100. Hope this makes a little sense? Good Luck