Smurfsnot2604 Posts: 6, Reputation: 1 New Member #1 Jul 15, 2009, 02:20 PM
system of equations
A farmer has 1,200 acres of land on which he grows corn, wheat, and soybeans. It costs \$45 per acre to grow corn, \$60 for wheat, and \$50 for soybeans. Because of market demand he will grow twice as many acres of wheat as of corn. He has allocated \$63,750 for the cost of growing his crops. How many acres of each crop should he plant?
 galactus Posts: 2,271, Reputation: 282 Ultra Member #2 Jul 15, 2009, 03:01 PM
Let c, w, and s be the acres of the respective crops to be planted.

c=corn, w=wheat, s=soybean

We are told he has 1200 acres to plant.

Therefore, c+w+s=1200

One condition is that there is twice as much wheat as corn, 2c=w

The final equation is the cost, 45c+60w+50s=63,750

Now, you have three equations and three unknowns.

Solve using substitution or elimination. The condition 2c=w helps simplify it down to two equations easy enough.

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