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    ray17molly89's Avatar
    ray17molly89 Posts: 1, Reputation: 1
    New Member
    		  
    #1

    Nov 30, 2009, 04:49 PM
    solving radical expressions
    -5sqrt12 - 6sqrt27 - 3sqrt48
    mathwiz3502's Avatar
    mathwiz3502 Posts: 121, Reputation: 1
    Junior Member
    		  
    #2

    Nov 30, 2009, 05:19 PM
    Guessing that you are taking 9th grade math, here is how you do it:
    for simplifying radicals find perfect square factors of what's under, and multiply what's left by its square root
    ex. Sqrt50
    50=25 times 2
    sqrt50=5sqrt2
    1.-5sqrt12
    12=4 times 3
    -5sqrt12=-10sqrt3
    2.6sqrt27
    27=3 times 9
    6sqrt27=18sqrt3
    3.3sqrt48
    48=16 times 3
    3sqrt48=12sqrt3
    -10sqrt3 + -18sqrt3 + -12sqrt3
    with like terms we can now subtract to
    -40sqrt3
    g13544055's Avatar
    g13544055 Posts: 22, Reputation: 2
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    #3

    Dec 1, 2009, 11:09 AM

    it's important to know that mathwiz is using the rule ./(a.b) = (./a) x (./b)

    i.e. . /50 = ./(25x2) = (./25) x (./2)
    = 5./2

    (where I'm using ./ to mean sqrt)
    mathwiz3502's Avatar
    mathwiz3502 Posts: 121, Reputation: 1
    Junior Member
    		  
    #4

    Dec 1, 2009, 03:18 PM
    Correct g13544055
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