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    brijmohan123456's Avatar
    brijmohan123456 Posts: 41, Reputation: 1
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    #1

    Nov 16, 2012, 09:18 AM
    solve
    [{(39.2)^(2)*sin(x)^(2)}+980]/(2*9.8)={(39.2)^2*cos(x)^2}/(*·9.8)
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #2

    Nov 16, 2012, 10:07 AM
    Should the denominator of the right hand side be "2 * 9.8"? If so, the denominators of both sides cancel, and you can rearrange this to be of the form C = cos^2x - sin^2c, where 'C' is a constant. Recall that cos(2x) = cos^2x - sin^2x, so this simplifies to an equation of the form cos(2x) = C, and you can solve for x by taking the arccosine of both sides.
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