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    pem1840's Avatar
    pem1840 Posts: 1, Reputation: 1
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    #1

    Apr 7, 2014, 03:37 PM
    Two full 48-gallon tanks begin draining at t = 0. Tank Alpha's volume is changing at
    Two full 48-gallon tanks begin draining at t = 0. Tank Alpha's volume is changing
    at a constant rate of -16/5 gal/min. The rate at which Tank Bravo's volume is
    changing is given by r(t)=-1/3t-1 gal/min.

    a) How much water is in each tank after 5 minutes?
    b) Which tub drains rst? How do you know?
    CWH68's Avatar
    CWH68 Posts: 26, Reputation: 2
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    #2

    Apr 20, 2014, 07:26 PM
    Hint: The water in tank alpha is wa(t) = 48 - (16/5)t
    t/
    The water in tank bravo is wb(t) = 48 + | (-(t/3) -1) dt.
    0/

    I assume that tank bravo drains at rate r(t) = (-(t/3) - 1) and not
    r(t) = -(1/3t) -1 or r(t) = -1/(3t - 1), otherwise, the integral would diverge.

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