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    Help18's Avatar
    Help18 Posts: 1, Reputation: 1
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    #1

    Nov 3, 2011, 11:41 AM
    How to find a vertical asymptote of denominator (2x^2-x-6)?
    How do you find a vertical asymptote of denominator (2x^2-x-6)?
    ArcSine's Avatar
    ArcSine Posts: 969, Reputation: 106
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    #2

    Nov 3, 2011, 12:40 PM
    Find the two zeros of that quadratic. Then evaluate the numerator at each of those x-values. If the numerator is nonzero at either one, you're looking at a vert asymptote at that x-val.

    (I'm assuming from your description that the expression you gave is the denominator of a rational function. If not, all bets are off and you'll need to check back in with more details.)

    Good luck with it.
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