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    Wikkibahi's Avatar
    Wikkibahi Posts: 42, Reputation: 1
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    #1

    May 15, 2011, 12:48 AM
    Locus Problem in complex number..
    Find the locus of points in the plane satisfying each of the given conditions:
    (i) |z-5| = 6 (ii) |z-2i| >=1 (iii) Re(z+2) = -1
    (iv) Re{i(conjugate of z)} =3 (v) |z+i| = |z-i|
    Also Sketch its diagram.
    Please tell me as soon as possible...?
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #2

    May 15, 2011, 02:40 AM

    The locus of an equation of the forms:



    Is a circle with centre (x, y) and radius r.
    The equal sign indicates that the locus is on the circumference. If that were to be replaced by a sign, this will be on and outside the circumference of the circle.



    That means that the real part of z + x gives p, meaning that the real part of z is equal to p - x.



    The locus of this is a line, along the perpendicular bisector of the line joining the points (x, y) and (a, b)

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