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    cute.2's Avatar
    cute.2 Posts: 1, Reputation: 1
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    #1

    Mar 12, 2011, 05:52 AM
    proving identities
    sec times tan times sin equals?
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #2

    Mar 13, 2011, 02:59 AM

    Is that:



    ?

    Convert the sec and tan ratios into sin and cos ratios first.
    xx_hannah_xx's Avatar
    xx_hannah_xx Posts: 1, Reputation: 1
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    #3

    Mar 13, 2011, 04:47 AM
    if it is secθ x tanθ x sinθ , then its pretty simple
    secθ = 1/tanθ
    1/tanθ x tanθ x sinθ
    the 1/tanθ will cancel with the tanθ
    so
    secθ x tanθ x sinθ = sinθ since the first two terms cancel each other out
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #4

    Mar 13, 2011, 04:52 AM
    Quote Originally Posted by xx_hannah_xx View Post
    if it is secθ x tanθ x sinθ , then its pretty simple
    secθ = 1/tanθ
    1/tanθ x tanθ x sinθ
    the 1/tanθ will cancel with the tanθ
    so
    secθ x tanθ x sinθ = sinθ since the first two terms cancel each other out
    That is not correct.


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