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    Moonunit's Avatar
    Moonunit Posts: 2, Reputation: 1
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    #1

    Feb 6, 2011, 01:02 PM
    Find the nth term and the 100th term 4,15,30,49,72... nth... Find the 100th term
    4,15,30,49,72... nth... Find the nth term and the 100th term of the sequence.
    jcaron2's Avatar
    jcaron2 Posts: 986, Reputation: 204
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    #2

    Feb 6, 2011, 02:56 PM

    If you look at the difference between the first two numbers (4 and 15), you'll see it's 11. The next two (15 and 30), differ by 15. The next two differ by 19, then 23, etc. Notice that the difference increases by 4 each time.

    That works out so that the nth term = 2n(n+1)+3n-3 or 2n^2 + 5n - 3. So the 100th term is 100^2 + 5*100 -3 = 10000 + 500 - 3 = 10497.
    Moonunit's Avatar
    Moonunit Posts: 2, Reputation: 1
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    #3

    Feb 6, 2011, 04:45 PM
    Comment on jcaron2's post
    Thank you, I couldn't have even come close.
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #4

    Feb 7, 2011, 08:04 AM

    Using the formula that jcaron2 supplied, the 100th term is actually 2*100^2 + 5*100 -3 = 20,497.
    jcaron2's Avatar
    jcaron2 Posts: 986, Reputation: 204
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    #5

    Feb 8, 2011, 04:16 PM
    Quote Originally Posted by ebaines View Post
    Using the formula that jcaron2 supplied, the 100th term is actually 2*100^2 + 5*100 -3 = 20,497.
    :o

    Oops.

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