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    mimss's Avatar
    mimss Posts: 1, Reputation: 1
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    #1

    Nov 14, 2010, 05:41 AM
    how to prove this using epsilon delta lim x->3 x^2-9/x 3 = -6
    lim x^2-9/x+3 = -6
    x-->3
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #2

    Nov 14, 2010, 06:47 AM
    I think that you meant:


    What happens if you factorise the denominator? :)
    galactus's Avatar
    galactus Posts: 2,271, Reputation: 282
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    #3

    Nov 14, 2010, 06:51 AM

    Please use proper grouping symbols. You are in calculus.

    Are you sure there is not a typo.
    x should perhaps approach -3 instead of 3?

    Here's why I ask:

    The numerator is a difference of two squares.





    If x approached 3, the limit would be 0.
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