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    pauldaoctorpus's Avatar
    pauldaoctorpus Posts: 12, Reputation: 1
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    #1

    Sep 1, 2010, 09:13 PM
    Help Practicing ?
    A box contains 5 red and 5 blue balls. Two balls are withdrawn randomly. If they are the same color, then you win NT$11 dollars. However, if they are different colors, then you win –NT$ 10 dollars (that is, you lose NT$ 10 dollars). Calculate
    (a) the expected value of the money you win.
    (b) the variance of the money you win.








    I will be Glad if you can help me !
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #2

    Sep 1, 2010, 09:54 PM

    First, you need to put up a probability distribution function (PDF).

    Let X be the amount of money you win.




    Now you need to fill in the table. What is the probability of getting -NT$ 10?
    That is the probability that you pick a red then a blue, or a blue then a red. Can you find this?

    Then, put the probability in the table under -10

    Do the same with the next one, gaining NT$ 11. (That is P(blue, blue or red red))

    Once you filled in the table, you can go to the first part.

    Expected value is obtained by adding XP(X=x). That is, multiply the probability with its event. Say you had 1/2 for the event you lose NT$ 10, and half for gaining NT$ 11, then the expected value will be

    E(X) = (0.5 x -10) + (0.5 x 11) = -5 + 5.5 = NT$ 0.5

    Variance is obtained by:



    E(X^2) is taking first the square of the event and multiplying this with the corresponding probability.
    E^2(X) is just the square of your expected value.

    Post what you get! :)

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