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    MRBEE's Avatar
    MRBEE Posts: 3, Reputation: 1
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    #1

    Apr 2, 2008, 04:10 PM
    probability of being seated together
    Three married couples are to be randomly seated around a circular table. What is the probability that at least one of the couples will be seated next to one another?
    galactus's Avatar
    galactus Posts: 2,271, Reputation: 282
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    #2

    Apr 2, 2008, 06:16 PM
    When seating in a circular permutations, there are (n-1)! Ways to do so without restriction.

    In this case, 5!=120 ways to seat the 3 couples(6 people) without restriction.

    The opposite of 'at least one' is none. So, find the probability of no couples sitting together

    and subtract from 1. Or find the number of ways 1 couple can sit together, 2 couples, and

    three couples can sit together and add them up.

    For two couples together, we can choose 2 pairs in C(3,2)=3 ways and this pair can be

    arranged in 2 ways. The next pair in 2 ways and the next pair in two ways.

    So, we have ways for two couples to be seated together.

    Following the same logic, there are ways for 1 couple to be

    seated together and ways for all three to be seated together.

    Therefore, we have 16+24+48=88 ways for at least one couple to be seated together.

    The probability would be 88/120=11/15.

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