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    jsham996's Avatar
    jsham996 Posts: 1, Reputation: 1
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    #1

    Jan 31, 2008, 02:43 AM
    how to solve it
    log (x + 17) - log (x - 1) + log (x) = 1
    jiten55's Avatar
    jiten55 Posts: 105, Reputation: 8
    Junior Member
    		  
    #2

    Jan 31, 2008, 04:15 AM
    Assuming base for log is 10:

    log (x + 17) - log (x - 1) + log (x) = 1

    [Log A + Log B - Log C = Log [(AB)/C] and 1 = Log 10 , assuming base is 10]

    Log [(x +17)x/(x -1) ] = Log 10

    (x +17)x/(x -1) = 10

    x(x +17) = 10(x -1)

    Solve this quadratic equation.
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